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4.9x^2+6x-4=0
a = 4.9; b = 6; c = -4;
Δ = b2-4ac
Δ = 62-4·4.9·(-4)
Δ = 114.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-\sqrt{114.4}}{2*4.9}=\frac{-6-\sqrt{114.4}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+\sqrt{114.4}}{2*4.9}=\frac{-6+\sqrt{114.4}}{9.8} $
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